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  meneka1  

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by meneka1
5-10-16
OK, for example y=csc(x+pi/2), amplitude is 1, period is 2pi, phase shift is -pi/2, vertical shift is none, start is -pi/2, the end is 3pi/2, and increments is pi/2
Ok, i got it now... how do i graph the secant and cosecant?
You graph the cosecant by using y=cscx and the identity of cscx=1/sin and sinx=0, the cosecant function is undefined. It's graph has vertical asymptotes.
What are the properties of cscx?
First you have the domain which is x, then you have the range, now the period and you have the vertical asymptotes.
Alright thanks, you broke it down perfectly for me! I have one more question for you, what is a trigonometric identity?
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