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| Do you know how to find angle ACB in this cube? | |
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| Yeah! Since the line segment AB is perpendicular to the sides of the base so angle B is 90 degrees. | |
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| It's a right angle triangle! Do I use SOH CAH TOA to find angle ACB? | |
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| Exactly. First you label the line segment AB as x. | |
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| And then you label line segment CB as 2x. | |
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