|
|
|
|
 | |  |
| So now it is (c-a) + (e-c) + (e+a) = 30. Then you take out the A's and the C's, and it is 2e = 30. To get rid of the 2, you will have to divide both by 2. So it ends off with e=15. | |
 | |  |
|
 |
|
|
|
|
|
|
| | |
| h-e=7 right? Now you sub in e=15, so you get h-15=7. Then you bring the -15 onto the other side to isolate h to get h=7+15. There you go, H is equal to 22. | |
| | |
|
|
|
|
|
|
|
|
| | |
| f+g=h. Since we know that h=22, we will plug that into the equation to get F+G=22. We also know that F is equal to a+e, so we plug that in to get a+e+g=22. | |
| | |
|
 |
|
|
